sml - Can I fold with an infix operator without writing out an anonymous function? -

sml - Can I fold with an infix operator without writing out an anonymous function? -

if wanted add together list this:

- list.foldr (fn (x, y) => x + y) 0 [1, 2, 3] val = 6 : int

is there way write more along lines of:

list.foldr + 0 [1, 2, 3]

i tried this:

fun inf2f op = fn (x, y) => x op y;

you're close. add together op keyword in sec example.

- list.foldr op + 0 [1,2,3]; val = 6 : int

sml syntactic-sugar