shell - How do I get the script name being executed in bash? -

shell - How do I get the script name being executed in bash? -

so trying create portable bashrc/bash_profile file. have single script symbolically linking .bashrc, .bash_profile, etc. looking @ $0 , switching based on script called. problem shell calls bashrc script of course of study executes bash means $0 me -bash. $1 farther more not set script name.

so question is, in bash how can name of script beingness executed. not binary executing it, e.g. bash?

i assume giving me -bash $1 not beingness set because not new process. ideas?

the variable bash_argv should work, appears script being sourced

$bash_argv

bash shell .bash-profile