javascript - js, $.inArray, not returning expected returns -

javascript - js, $.inArray, not returning expected returns -

i want inquire question why not working?

http://jsfiddle.net/2fmue/4/

var = $('input').attr('value').split(','); if(a instanceof array) alert(1); if($.inarray($('#id').text(), a)) alert(2); if($.inarray('united state', a)) alert(3); // array no homecoming right match.

i split value array , utilize $.inarray check string has in array.

but not homecoming right index.

i dont know wrong in example. please advice.

thank much.

it works well.

$.inarray returns index of element found in given array (or -1 if not found).

as example,

$.inarray("united state", ["united state", "america"]) === 0 $.inarray("unknown", ["united state", "america"]) === -1

so, in order check if element exists in array have use:

if ($.inarray("unknown", ["united state", "america"]) > -1) { // ... }

javascript jquery arrays match