c - Is size of char * same as size of int *? -

c - Is size of char * same as size of int *? -

i know: char * pointer char. , int * pointer int.

so, want confirm next 2 things:

so suppose on 32 bit machine, means memory addresses 32 bit wide. means size of char * , int * both 32 bits ( 4 bytes), right ? size of char * * same size of int * ?

suppose have: int * ptr;

thus doing *((char * *) ptr) = 0x154 same *((int *) ptr) = 0x514 same, right ? ( 0x514 random memory address)

platform: on x86.

p.s.: know type casting not suggested way code. doing kernel coding, have type casting !

in c pointers not guaranteed have same size. in reality implementations pointers same size, implementation detail of compiler.

from c faq:

the old hp 3000 series uses different addressing scheme byte addresses word addresses; several of machines above hence uses different representations char * , void * pointers other pointers

depending on ``memory model'' in use, 8086-family processors (pc compatibles) may utilize 16-bit info pointers , 32-bit function pointers, or vice versa.

also *((char *)ptr) = 0x154 not same *((int *)ptr) = 0x154. because dereferencing pointer write info size of char , size of int location pointed ptr. assuming 8 bit char , 32 bit int, *((char *)ptr) = 0x154 write0x154 memory address assigned ptr , *((int *)ptr) = 0x154 write 0x0000000154 4 bytes starting @ address assigned ptr.

c pointers assembly dereference