c - Using write() to print to console -

c - Using write() to print to console -

so trying create function uses write() scheme phone call (printf , other options not available) output string console. however, nail snag.

here function:

static void doprint (const char *s) { write (stdout_fileno, s, sizeof(s)); }

which beingness called by:

doprint ("hello world!\n");

however, prints out:

hello wo

what doing wrong?

note: access stdlib , stdio restricted

thanks

in context sizeof doesn't want - yields size of pointer, not size of string. utilize strlen instead.

but access stdlib restricted

you can roll own using while , counter. untested:

size_t my_strlen(const char *s) { size_t len = 0; while (*s++) len++; homecoming len; }

or more efficient version:

size_t my_strlen(const char* s) { const char *end = s; while (*end++) {}; homecoming end-s-1; }

the above works because pointer advanced lastly position in string , size difference between lastly pointer location , first pointer location, minus 1 of course of study handle null-terminating character.

c